If it's not what You are looking for type in the equation solver your own equation and let us solve it.
8p^2+3p-160=0
a = 8; b = 3; c = -160;
Δ = b2-4ac
Δ = 32-4·8·(-160)
Δ = 5129
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-\sqrt{5129}}{2*8}=\frac{-3-\sqrt{5129}}{16} $$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+\sqrt{5129}}{2*8}=\frac{-3+\sqrt{5129}}{16} $
| 51=12x-9 | | -9x-8=-5x-8+9 | | 7x-3(12x+10)=-4(x-5) | | 6x–7+3=32+3x | | 6z-4z=18 | | (x+1)/3=4 | | 9x=19x+6 | | -5x-8=-5x-8+9x | | (8x-11)=2x+6+5x | | 4(x-6)-5=-29 | | 5x-8=-5x-8+9 | | 4(5+x)=20+5x-1x | | 3x14/2=4 | | 4(1+8x)=2x+34 | | .28=82+104/x | | x9=91 | | X+5+2x-4=11 | | 4=3x14/2 | | 4x-20=4x+7 | | 7=2(z-11)-9 | | (6x+4)+(5x-33)=180 | | $495.55=34.95u+6.25 | | (5m+100)+(2m+10)=180,m | | 2|2x-5|+9=9 | | ?x9=91 | | 24x=12(39-x) | | 3(2x+7)=-11+20 | | 1=–3x–5 | | 9+2.75(8x)=12 | | 1x=–3x–5 | | 5x-2(4x+5)=5 | | 46+x/6−21=25+6 |